How do I POST urlencoded form data with $http without jQuery?

I am new to AngularJS, and for a start, I thought to develop a new application using only AngularJS.

I am trying to make an AJAX call to the server side, using $http from my Angular App.

For sending the parameters, I tried the following:

    method: "post",
    url: URL,
    headers: {'Content-Type': 'application/x-www-form-urlencoded'},
    data: $.param({username: $scope.userName, password: $scope.password})

This is working, but it is using jQuery as well at $.param. For removing the dependency on jQuery, I tried:

data: {username: $scope.userName, password: $scope.password}

but this seemed to fail. Then I tried params:

params: {username: $scope.userName, password: $scope.password}

but this also seemed to fail. Then I tried JSON.stringify:

data: JSON.stringify({username: $scope.userName, password: $scope.password})

I found these possible answers to my quest, but was unsuccessful. Am I doing something wrong? I am sure, AngularJS would provide this functionality, but how?



I think you need to do is to transform your data from object not to JSON string, but to url params.

From Ben Nadel's blog.

By default, the $http service will transform the outgoing request by serializing the data as JSON and then posting it with the content- type, "application/json". When we want to post the value as a FORM post, we need to change the serialization algorithm and post the data with the content-type, "application/x-www-form-urlencoded".

Example from here.

    method: 'POST',
    url: url,
    headers: {'Content-Type': 'application/x-www-form-urlencoded'},
    transformRequest: function(obj) {
        var str = [];
        for(var p in obj)
        str.push(encodeURIComponent(p) + "=" + encodeURIComponent(obj[p]));
        return str.join("&");
    data: {username: $scope.userName, password: $scope.password}
}).then(function () {});


To use new services added with AngularJS V1.4, see


URL-encoding variables using only AngularJS services

With AngularJS 1.4 and up, two services can handle the process of url-encoding data for POST requests, eliminating the need to manipulate the data with transformRequest or using external dependencies like jQuery:

  1. $httpParamSerializerJQLike - a serializer inspired by jQuery's .param() (recommended)

  2. $httpParamSerializer - a serializer used by Angular itself for GET requests

Example usage

  url: 'some/api/endpoint',
  method: 'POST',
  data: $httpParamSerializerJQLike($, // Make sure to inject the service you choose to the controller
  headers: {
    'Content-Type': 'application/x-www-form-urlencoded' // Note the appropriate header
}).then(function(response) { /* do something here */ });

See a more verbose Plunker demo

How are $httpParamSerializerJQLike and $httpParamSerializer different

In general, it seems $httpParamSerializer uses less "traditional" url-encoding format than $httpParamSerializerJQLike when it comes to complex data structures.

For example (ignoring percent encoding of brackets):

Encoding an array

{sites:['google', 'Facebook']} // Object with array property

sites[]=google&sites[]=facebook // Result with $httpParamSerializerJQLike

sites=google&sites=facebook // Result with $httpParamSerializer

Encoding an object

{address: {city: 'LA', country: 'USA'}} // Object with object property

address[city]=LA&address[country]=USA // Result with $httpParamSerializerJQLike

address={"city": "LA", country: "USA"} // Result with $httpParamSerializer

All of these look like overkill (or don't work)... just do this:

$, "userName=" + encodeURIComponent(email) +
                     "&password=" + encodeURIComponent(password) +
).success(function (data) {

The problem is the JSON string format, You can use a simple URL string in data:

    method: 'POST',
    url: url,
    headers: {'Content-Type': 'application/x-www-form-urlencoded'},
    data: 'username='+$scope.userName+'&password='+$scope.password
}).success(function () {});

Here is the way it should be (and please no backend changes ... certainly not ... if your front stack does not support application/x-www-form-urlencoded, then throw it away ... hopefully AngularJS does !

     method: 'POST',
     url: 'api_endpoint',
     headers: {'Content-Type': 'application/x-www-form-urlencoded'},
     data: 'username='+$scope.username+'&password='+$scope.password
 }).then(function(response) {
    // on success
 }, function(response) {
    // on error

Works like a charm with AngularJS 1.5

People, let give u some advice:

  • use promises .then(success, error) when dealing with $http, forget about .sucess and .error callbacks (as they are being deprecated)

  • From the angularjs site here "You can no longer use the JSON_CALLBACK string as a placeholder for specifying where the callback parameter value should go."

If your data model is more complex that just a username and a password, you can still do that (as suggested above)

     method: 'POST',
     url: 'api_endpoint',
     headers: {'Content-Type': 'application/x-www-form-urlencoded'},
     data: json_formatted_data,
     transformRequest: function(data, headers) {
          return transform_json_to_urlcoded(data); // iterate over fields and chain key=value separated with &, using encodeURIComponent javascript function
}).then(function(response) {
  // on succes
}, function(response) {
  // on error

Document for the encodeURIComponent can be found here


If it is a form try changing the header to:

headers[ "Content-type" ] = "application/x-www-form-urlencoded; charset=utf-8";

and if it is not a form and a simple json then try this header:

headers[ "Content-type" ] = "application/json";

    method: "POST",
    url: "/server.php",
    headers: { 'Content-Type': 'application/x-www-form-urlencoded' },
    data: "name='????'&age='28'",

}).success(function(data, status) {

From the $http docs this should work..

  $, data,{headers: {'Content-Type': 'application/x-www-form-urlencoded'}})
    .success(function(response) {
         // your code...

you need to post plain javascript object, nothing else

           var request = $http({
                method: "post",
                url: "process.cfm",
                transformRequest: transformRequestAsFormPost,
                data: { id: 4, name: "Kim" }

                function( data ) {
                    $scope.localData = data;

if you have php as back-end then you will need to do some more modification.. checkout this link for fixing php server side


Though a late answer, I found angular UrlSearchParams worked very well for me, it takes care of the encoding of parameters as well.

let params = new URLSearchParams();
params.set("abc", "def");

let headers = new Headers({ 'Content-Type': 'application/x-www-form-urlencoded'});
let options = new RequestOptions({ headers: headers, withCredentials: true });
.post(UrlUtil.getOptionSubmitUrl(parentSubcatId), params, options)

This worked for me. I use angular for front-end and laravel php for back-end. In my project, angular web sends json data to laravel back-end.

This is my angular controller.

var angularJsApp= angular.module('angularJsApp',[]);
angularJsApp.controller('MainCtrl', function ($scope ,$http) {

    $scope.userName ="Victoria";
    $scope.password ="password"

            method :'POST',
            data: { username :  $scope.userName , password: $scope.password},
            headers: {'Content-Type': 'application/json'}
        }).success(function (data, status, headers, config) {


This is my php back-end laravel controller.

public function httpTest(){
        if (Input::has('username')) {
            $user =Input::all();
            return  Response::json($user)->setCallback(Input::get('callback'));

This is my laravel routing

Route::post('httpTest','[email protected]');

The result in browser is

status 200
data JSON_CALLBACK({"username":"Victoria","password":"password","callback":"JSON_CALLBACK"}); httpTesting.js:18 headers function (c){a||(a=sc(b));return c?a[K(c)]||null:a}

There is chrome extension called postman. You can use to test your back-end url whether it is working or not.

hopefully, my answer will help you.


Recent Questions

Top Questions

Home Tags Terms of Service Privacy Policy DMCA Contact Us Javascript

©2020 All rights reserved.