How to loop through an array containing objects and access their properties

I want to cycle through the objects contained in an array and change the properties of each one. If I do this:

for (var j = 0; j < myArray.length; j++){

console.log(myArray[j]);

}

The console should bring up every object in the array, right? But in fact it only displays the first object. if I console log the array outside of the loop, all the objects appear so there's definitely more in there.

Anyway, here's the next problem. How do I access, for example Object1.x in the array, using the loop?

for (var j = 0; j < myArray.length; j++){

console.log(myArray[j.x]);

}

This returns "undefined." Again the console log outside the loop tells me that the objects all have values for "x". How do I access these properties in the loop?

I was recommended elsewhere to use separate arrays for each of the properties, but I want to make sure I've exhausted this avenue first.

Thank you!

Answers:

Answer

Use forEach its a built-in array function. Array.forEach():

yourArray.forEach(function (arrayItem) {
    var x = arrayItem.prop1 + 2;
    console.log(x);
});
Answer

Some use cases of looping through an array in the functional programming way in JavaScript:

1. Just loop through an array

const myArray = [{x:100}, {x:200}, {x:300}];

myArray.forEach((element, index, array) => {
    console.log(element.x); // 100, 200, 300
    console.log(index); // 0, 1, 2
    console.log(array); // same myArray object 3 times
});

Note: Array.prototype.forEach() is not a functional way strictly speaking, as the function it takes as the input parameter is not supposed to return a value, which thus cannot be regarded as a pure function.

2. Check if any of the elements in an array pass a test

const people = [
    {name: 'John', age: 23}, 
    {name: 'Andrew', age: 3}, 
    {name: 'Peter', age: 8}, 
    {name: 'Hanna', age: 14}, 
    {name: 'Adam', age: 37}];

const anyAdult = people.some(person => person.age >= 18);
console.log(anyAdult); // true

3. Transform to a new array

const myArray = [{x:100}, {x:200}, {x:300}];

const newArray= myArray.map(element => element.x);
console.log(newArray); // [100, 200, 300]

Note: The map() method creates a new array with the results of calling a provided function on every element in the calling array.

4. Sum up a particular property, and calculate its average

const myArray = [{x:100}, {x:200}, {x:300}];

const sum = myArray.map(element => element.x).reduce((a, b) => a + b, 0);
console.log(sum); // 600 = 0 + 100 + 200 + 300

const average = sum / myArray.length;
console.log(average); // 200

5. Create a new array based on the original but without modifying it

const myArray = [{x:100}, {x:200}, {x:300}];

const newArray= myArray.map(element => {
    return {
        ...element,
        x: element.x * 2
    };
});

console.log(myArray); // [100, 200, 300]
console.log(newArray); // [200, 400, 600]

6. Count the number of each category

const people = [
    {name: 'John', group: 'A'}, 
    {name: 'Andrew', group: 'C'}, 
    {name: 'Peter', group: 'A'}, 
    {name: 'James', group: 'B'}, 
    {name: 'Hanna', group: 'A'}, 
    {name: 'Adam', group: 'B'}];

const groupInfo = people.reduce((groups, person) => {
    const {A = 0, B = 0, C = 0} = groups;
    if (person.group === 'A') {
        return {...groups, A: A + 1};
    } else if (person.group === 'B') {
        return {...groups, B: B + 1};
    } else {
        return {...groups, C: C + 1};
    }
}, {});

console.log(groupInfo); // {A: 3, C: 1, B: 2}

7. Retrieve a subset of an array based on particular criteria

const myArray = [{x:100}, {x:200}, {x:300}];

const newArray = myArray.filter(element => element.x > 250);
console.log(newArray); // [{x:300}] 

Note: The filter() method creates a new array with all elements that pass the test implemented by the provided function.

8. Sort an array

const people = [
  { name: "John", age: 21 },
  { name: "Peter", age: 31 },
  { name: "Andrew", age: 29 },
  { name: "Thomas", age: 25 }
];

let sortByAge = people.sort(function (p1, p2) {
  return p1.age - p2.age;
});

console.log(sortByAge);

enter image description here

9. Find an element in an array

const people = [ {name: "john", age:23},
                {name: "john", age:43},
                {name: "jim", age:101},
                {name: "bob", age:67} ];

const john = people.find(person => person.name === 'john');
console.log(john);

enter image description here

The Array.prototype.find() method returns the value of the first element in the array that satisfies the provided testing function.

References

Answer
for (var j = 0; j < myArray.length; j++){
  console.log(myArray[j].x);
}
Answer

Here's an example on how you can do it :)

var students = [{
    name: "Mike",
    track: "track-a",
    achievements: 23,
    points: 400,
  },
  {
    name: "james",
    track: "track-a",
    achievements: 2,
    points: 21,
  },
]

students.forEach(myFunction);

function myFunction(item, index) {
  for (var key in item) {
    console.log(item[key])
  }
}

Answer

Looping through an array of objects is a pretty fundamental functionality. This is what works for me.

var person = [];
person[0] = {
  firstName: "John",
  lastName: "Doe",
  age: 60
};

var i, item;

for (i = 0; i < person.length; i++) {
  for (item in person[i]) {
    document.write(item + ": " + person[i][item] + "<br>");
  }
}

Answer

myArray[j.x] is logically incorrect.

Use (myArray[j].x); instead

for (var j = 0; j < myArray.length; j++){
  console.log(myArray[j].x);
}
Answer

It's really simple using the forEach method since ES5+. You can directly change each property of each object in your array.

myArray.forEach(function (arrayElem){ 
  arrayElem = newPropertyValue;
});

If you want to access a specific property on each object:

myArray.forEach(function (arrayElem){ 
      arrayElem.nameOfYourProperty = newPropertyValue;
    });
Answer

Here's another way of iterating through an array of objects (you need to include jQuery library in your document for these).

$.each(array, function(element) {
  // do some operations with each element... 
});
Answer

This would work. Looping thorough array(yourArray) . Then loop through direct properties of each object (eachObj) .

yourArray.forEach( function (eachObj){
    for (var key in eachObj) {
        if (eachObj.hasOwnProperty(key)){
           console.log(key,eachObj[key]);
        }
    }
});
Answer

Array object iteration, using jQuery, (use the second parameter to print the string).

$.each(array, function(index, item) {
       console.log(index, item);
});
Answer

Accepted answer uses normal function. So posting the same code with slight modification using arrow function on forEach

  yourArray.forEach(arrayItem => {
      var x = arrayItem.prop1 + 2;
      console.log(x);
  });

Also in $.each you can use arrow function like below

 $.each(array, (item, index) => {
       console.log(index, item);
 });
Answer

You can use a for..of loop to loop over an array of objects.

for (let item of items) {
    console.log(item); // Will display contents of the object inside the array
}

One of the best things about for..of loops is that they can iterate over more than just arrays. You can iterate over any type of iterable, including maps and objects. Make sure you use a transpiler or something like TypeScript if you need to support older browsers.

Answer

var c = {
    myProperty: [
        { name: 'this' },
        { name: 'can' },
        { name: 'get' },
        { name: 'crazy' }
    ]
};

c.myProperty.forEach(function(myProperty_element) {
    var x = myProperty_element.name;
    console.log('the name of the member is : ' + x);
})

This is one of the ways how I was able to achieve it.

Answer

const jobs = [
    {
        name: "sipher",
        family: "sipherplus",
        job: "Devops"
    },
    {
        name: "john",
        family: "Doe",
        job: "Devops"
    },
    {
        name: "jim",
        family: "smith",
        job: "Devops"
    }
];

const txt = 
   ` <ul>
        ${jobs.map(job => `<li>${job.name} ${job.family} -> ${job.job}</li>`).join('')}
    </ul>`
;

document.body.innerHTML = txt;

Be careful about the back Ticks (`)

Answer

This might help somebody. Maybe it's a bug in Node.

var arr = [ { name: 'a' }, { name: 'b' }, { name: 'c' } ];
var c = 0;

This doesn't work:

while (arr[c].name) { c++; } // TypeError: Cannot read property 'name' of undefined

But this works...

while (arr[c]) { c++; } // Inside the loop arr[c].name works as expected.

This works too...

while ((arr[c]) && (arr[c].name)) { c++; }

BUT simply reversing the order does not work. I'm guessing there's some kind of internal optimization here that breaks Node.

while ((arr[c].name) && (arr[c])) { c++; }

Error says the array is undefined, but it's not :-/ Node v11.15.0

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