How to check a radio button with jQuery?

I try to check a radio button with jQuery. Here's my code:

<form>
    <div id='type'>
        <input type='radio' id='radio_1' name='type' value='1' />
        <input type='radio' id='radio_2' name='type' value='2' />
        <input type='radio' id='radio_3' name='type' value='3' /> 
    </div>
</form>

And the JavaScript:

jQuery("#radio_1").attr('checked', true);

Doesn't work:

jQuery("input[value='1']").attr('checked', true);

Doesn't work:

jQuery('input:radio[name="type"]').filter('[value="1"]').attr('checked', true);

Doesn't work:

Do you have another idea? What am I missing?

Answers:

Answer

For versions of jQuery equal or above (>=) 1.6, use:

$("#radio_1").prop("checked", true);

For versions prior to (<) 1.6, use:

$("#radio_1").attr('checked', 'checked');

Tip: You may also want to call click() or change() on the radio button afterwards. See comments for more info.

Answer

Try this.

In this example, I'm targeting it with its input name and value

$("input[name=background][value='some value']").prop("checked",true);

Good to know: in case of multi-word value, it will work because of apostrophes, too.

Answer

One more function prop() that is added in jQuery 1.6, that serves the same purpose.

$("#radio_1").prop("checked", true); 
Answer

Short and easy to read option:

$("#radio_1").is(":checked")

It returns true or false, so you can use it in "if" statement.

Answer

Try this.

To check Radio button using Value use this.

$('input[name=type][value=2]').attr('checked', true); 

Or

$('input[name=type][value=2]').attr('checked', 'checked');

Or

$('input[name=type][value=2]').prop('checked', 'checked');

To check Radio button using ID use this.

$('#radio_1').attr('checked','checked');

Or

$('#radio_1').prop('checked','checked');
Answer

The $.prop way is better:

$(document).ready(function () {                            
    $("#radio_1").prop('checked', true);        
});

and you can test it like the following:

$(document).ready(function () {                            
    $("#radio_1, #radio_2", "#radio_3").change(function () {
        if ($("#radio_1").is(":checked")) {
            $('#div1').show();
        }
        else if ($("#radio_2").is(":checked")) {
            $('#div2').show();
        }
        else 
            $('#div3').show();
    });        
});
Answer

Try This:

$("input[name=type]").val(['1']);

http://jsfiddle.net/nwo706xw/

Answer

You have to do

jQuery("#radio_1").attr('checked', 'checked');

That's the HTML attribute

Answer

If property name does not work don't forget that id still exists. This answer is for people who wants to target the id here how you do.

$('input[id=element_id][value=element_value]').prop("checked",true);

Because property name does not work for me. Make sure you don't surround id and name with double/single quotations.

Cheers!

Answer

Yes, it worked for me like a way:

$("#radio_1").attr('checked', 'checked');
Answer

Surprisingly, the most popular and accepted answer ignores triggering appropriate event despite of the comments. Make sure you invoke .change(), otherwise all the "on change" bindings will ignore this event.

$("#radio_1").prop("checked", true).change();
Answer
$("input[name=inputname]:radio").click(function() {
    if($(this).attr("value")=="yes") {
        $(".inputclassname").show();
    }
    if($(this).attr("value")=="no") {
        $(".inputclassname").hide();
    }
});
Answer

Get value:

$("[name='type'][checked]").attr("value");

Set value:

$(this).attr({"checked":true}).prop({"checked":true});

Radio Button click add attr checked:

$("[name='type']").click(function(){
  $("[name='type']").removeAttr("checked");
  $(this).attr({"checked":true}).prop({"checked":true});
});
Answer

We should want to tell it is a radio button.So please try with following code.

$("input[type='radio'][name='userRadionButtonName']").prop('checked', true);
Answer

Just in case anyone is trying to achieve this while using jQuery UI, you will also need to refresh the UI checkbox object to reflect the updated value:

$("#option2").prop("checked", true); // Check id option2
$("input[name='radio_options']").button("refresh"); // Refresh button set
Answer

Try this

$(document).ready(function(){
    $("input[name='type']:radio").change(function(){
        if($(this).val() == '1')
        {
          // do something
        }
        else if($(this).val() == '2')
        {
          // do something
        }
        else if($(this).val() == '3')
        {
          // do something
        }
    });
});
Answer

I use this code:

I'm sorry for English.

var $j = jQuery.noConflict();

$j(function() {
    // add handler
    $j('#radio-1, #radio-2').click(function(){

        // find all checked and cancel checked
        $j('input:radio:checked').prop('checked', false);

        // this radio add cheked
        $j(this).prop('checked', true);
    });
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<fieldset class="section">
  <legend>Radio buttons</legend>
  <label>
    <input type="radio" id="radio-1" checked>
    Option one is this and that&mdash;be sure to include why it's great
  </label>
  <br>
  <label>
    <input type="radio" id="radio-2">
    Option two can be something else
  </label>
</fieldset>

Answer

Try this with example

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<form id="myForm">
<input type="radio" name="radio" value="first"/> 1 <br/>
<input type="radio" name="radio" value="second"/> 2 <br/>
</form>


<script>
$(document).ready(function () {
    $('#myForm').on('click', function () {
        var value = $("[name=radio]:checked").val();

        alert(value);
    })
});
</script>
Answer

Try this

var isChecked = $("#radio_1")[0].checked;
Answer
function rbcitiSelction(e) {
     debugger
    $('#trpersonalemail').hide();
    $('#trcitiemail').show();
}

function rbpersSelction(e) {
    var personalEmail = $(e).val();
    $('#trpersonalemail').show();
    $('#trcitiemail').hide();
}

$(function() {  
    $("#citiEmail").prop("checked", true)
});
Answer
$("#radio_1").attr('checked', true);
//or
$("#radio_1").attr('checked', 'checked');
Answer

I got some related example to be enhanced, how about if I want to add a new condition, lets say, if I want colour scheme to be hidden after I click on project Status value except Pavers and Paving Slabs.

Example is in here:

$(function () {
    $('#CostAnalysis input[type=radio]').click(function () {
        var value = $(this).val();

        if (value == "Supply & Lay") {
            $('#ul-suplay').empty();
            $('#ul-suplay').append('<fieldset data-role="controlgroup"> \

http://jsfiddle.net/m7hg2p94/4/

Answer

In addition, you can check if the element is checked or not:

if ($('.myCheckbox').attr('checked'))
{
   //do others stuff
}
else
{
   //do others stuff
}

You can checked for unchecked element:

$('.myCheckbox').attr('checked',true) //Standards way

You can also uncheck this way:

$('.myCheckbox').removeAttr('checked')

You can checked for radio button:

For versions of jQuery equal or above (>=) 1.6, use:

$("#radio_1").prop("checked", true);

For versions prior to (<) 1.6, use:

$("#radio_1").attr('checked', 'checked');
Answer

I used jquery-1.11.3.js

Basic Enable & disable

Tips 1: (Radio button type common Disable & Enable)

$("input[type=radio]").attr('disabled', false);
$("input[type=radio]").attr('disabled', true); 

Tips 2: ( ID selector Using prop() or attr())

$("#paytmradio").prop("checked", true);
$("#sbiradio").prop("checked", false);

jQuery("#paytmradio").attr('checked', 'checked'); // or true this won't work
jQuery("#sbiradio").attr('checked', false);

Tips 3: ( Class selector Using prop() or arrt())

$(".paytm").prop("checked", true);
$(".sbi").prop("checked", false);

jQuery(".paytm").attr('checked', 'checked'); // or true
jQuery(".sbi").attr('checked', false);

OTHER TIPS

$("#paytmradio").is(":checked")   // Checking is checked or not
$(':radio:not(:checked)').attr('disabled', true); // All not check radio button disabled

$('input[name=payment_type][value=1]').attr('checked', 'checked'); //input type via checked
 $("input:checked", "#paytmradio").val() // get the checked value

index.html

<div class="col-md-6">      
    <label class="control-label" for="paymenttype">Payment Type <span style="color:red">*</span></label>
    <div id="paymenttype" class="form-group" style="padding-top: inherit;">
        <label class="radio-inline" class="form-control"><input  type="radio" id="paytmradio"  class="paytm" name="paymenttype" value="1" onclick="document.getElementById('paymentFrm').action='paytmTest.php';">PayTM</label>
        <label class="radio-inline" class="form-control"><input  type="radio" id="sbiradio" class="sbi" name="paymenttype" value="2" onclick="document.getElementById('paymentFrm').action='sbiTest.php';">SBI ePAY</label>
    </div>
</div>
Answer

try this

 $("input:checked", "#radioButton").val()

if checked returns True if not checked returns False

jQuery v1.10.1
Answer

Some times above solutions do not work, then you can try below:

jQuery.uniform.update(jQuery("#yourElementID").attr('checked',true));
jQuery.uniform.update(jQuery("#yourElementID").attr('checked',false));

Another way you can try is:

jQuery("input:radio[name=yourElementName]:nth(0)").attr('checked',true);
Answer

Try This:

$(document).ready(function(){
  $("#Id").prop("checked", true).checkboxradio('refresh');
});
Answer

I've just have a similar problem, a simple solution is to just use:

.click()

Any other solution will work if you refresh radio after calling function.

Answer

attr accepts two strings.

The correct way is:

jQuery("#radio_1").attr('checked', 'true');
Answer

In case you don't want to include a big library like jQuery for something this simple, here's an alternative solution using built-in DOM methods:

// Check checkbox by id:
document.querySelector('#radio_1').checked = true;

// Check checkbox by value:
document.querySelector('#type > [value="1"]').checked = true;

// If this is the only input with a value of 1 on the page, you can leave out the #type >
document.querySelector('[value="1"]').checked = true;
<form>
    <div id='type'>
        <input type='radio' id='radio_1' name='type' value='1' />
        <input type='radio' id='radio_2' name='type' value='2' />
        <input type='radio' id='radio_3' name='type' value='3' /> 
    </div>
</form>

Answer

Use prop() mehtod

enter image description here

Source Link

<p>
    <h5>Radio Selection</h5>

    <label>
        <input type="radio" name="myRadio" value="1"> Option 1
    </label>
    <label>
        <input type="radio" name="myRadio" value="2"> Option 2
    </label>
    <label>
        <input type="radio" name="myRadio" value="3"> Option 3
    </label>
</p>

<p>
    <button>Check Radio Option 2</button>
</p>


<script>
    $(function () {

        $("button").click(function () {
            $("input:radio[value='2']").prop('checked',true);
        });

    });
</script>

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