How to get the selected radio button’s value?

I’m having some strange problem with my JS program. I had this working properly but for some reason it’s no longer working. I just want to find the value of the radio button (which one is selected) and return it to a variable. For some reason it keeps returning undefined.

Here is my code:

function findSelection(field) {
    var test = 'document.theForm.' + field;
    var sizes = test;

    alert(sizes);
        for (i=0; i < sizes.length; i++) {
            if (sizes[i].checked==true) {
            alert(sizes[i].value + ' you got a value');     
            return sizes[i].value;
        }
    }
}

submitForm:

function submitForm() {

    var genderS =  findSelection("genderS");
    alert(genderS);
}

HTML:

<form action="#n" name="theForm">

    <label for="gender">Gender: </label>
    <input type="radio" name="genderS" value="1" checked> Male
    <input type="radio" name="genderS" value="0" > Female<br><br>
    <a href="javascript: submitForm()">Search</A>
</form>

Answers:

Answer

You can do something like this:

var radios = document.getElementsByName('genderS');

for (var i = 0, length = radios.length; i < length; i++) {
  if (radios[i].checked) {
    // do whatever you want with the checked radio
    alert(radios[i].value);

    // only one radio can be logically checked, don't check the rest
    break;
  }
}
<label for="gender">Gender: </label>
<input type="radio" name="genderS" value="1" checked="checked">Male</input>
<input type="radio" name="genderS" value="0">Female</input>

jsfiddle

Edit: Thanks HATCHA and jpsetung for your edit suggestions.

Answer

This works with any explorer.

document.querySelector('input[name="genderS"]:checked').value;

This is a simple way to get the value of any input type. You also do not need to include jQuery path.

Answer
document.forms.your-form-name.elements.radio-button-name.value
Answer

Since jQuery 1.8, the correct syntax for the query is

$('input[name="genderS"]:checked').val();

Not $('input[@name="genderS"]:checked').val(); anymore, which was working in jQuery 1.7 (with the @).

Answer

The simplest solution:

 document.querySelector('input[name=genderS]:checked').value
Answer

ECMAScript 6 version

let genderS = Array.from(document.getElementsByName("genderS")).find(r => r.checked).value;
Answer

Try this

function findSelection(field) {
    var test = document.getElementsByName(field);
    var sizes = test.length;
    alert(sizes);
    for (i=0; i < sizes; i++) {
            if (test[i].checked==true) {
            alert(test[i].value + ' you got a value');     
            return test[i].value;
        }
    }
}


function submitForm() {

    var genderS =  findSelection("genderS");
    alert(genderS);
    return false;
}

A fiddle here.

Answer

Edit: As said by Chips_100 you should use :

var sizes = document.theForm[field];

directly without using the test variable.


Old answer:

Shouldn't you eval like this ?

var sizes = eval(test);

I don't know how that works, but to me you're only copying a string.

Answer

This is pure JavaScript, based on the answer by @Fontas but with safety code to return an empty string (and avoid a TypeError) if there isn't a selected radio button:

var genderSRadio = document.querySelector("input[name=genderS]:checked");
var genderSValue = genderSRadio ? genderSRadio.value : "";

The code breaks down like this:

  • Line 1: get a reference to the control that (a) is an <input> type, (b) has a name attribute of genderS, and (c) is checked.
  • Line 2: If there is such a control, return its value. If there isn't, return an empty string. The genderSRadio variable is truthy if Line 1 finds the control and null/falsey if it doesn't.

For JQuery, use @jbabey's answer, and note that if there isn't a selected radio button it will return undefined.

Answer

In case someone was looking for an answer and landed here like me, from Chrome 34 and Firefox 33 you can do the following:

var form = document.theForm;
var radios = form.elements['genderS'];
alert(radios.value);

or simpler:

alert(document.theForm.genderS.value);

refrence: https://developer.mozilla.org/en-US/docs/Web/API/RadioNodeList/value

Answer

Here is an Example for Radios where no Checked="checked" attribute is used

function test() {
var radios = document.getElementsByName("radiotest");
var found = 1;
for (var i = 0; i < radios.length; i++) {       
    if (radios[i].checked) {
        alert(radios[i].value);
        found = 0;
        break;
    }
}
   if(found == 1)
   {
     alert("Please Select Radio");
   }    
}

DEMO : http://jsfiddle.net/ipsjolly/hgdWp/2/ [Click Find without selecting any Radio]

Source : http://bloggerplugnplay.blogspot.in/2013/01/validateget-checked-radio-value-in.html

Answer
 document.querySelector('input[name=genderS]:checked').value
Answer

Using a pure javascript, you can handle the reference to the object that dispatched the event.

function (event) {
    console.log(event.target.value);
}
Answer

lets suppose you need to place different rows of radio buttons in a form, each with separate attribute names ('option1','option2' etc) but the same class name. Perhaps you need them in multiple rows where they will each submit a value based on a scale of 1 to 5 pertaining to a question. you can write your javascript like so:

<script type="text/javascript">

    var ratings = document.getElementsByClassName('ratings'); // we access all our radio buttons elements by class name     
    var radios="";

    var i;
    for(i=0;i<ratings.length;i++){
        ratings[i].onclick=function(){
            var result = 0;
            radios = document.querySelectorAll("input[class=ratings]:checked");
            for(j=0;j<radios.length;j++){
                result =  result + + radios[j].value;
            }
            console.log(result);
            document.getElementById('overall-average-rating').innerHTML = result; // this row displays your total rating
        }
    }
</script>

I would also insert the final output into a hidden form element to be submitted together with the form.

Answer

If it is possible for you to assign a Id for your form element(), this way can be considered as a safe alternative way (specially when radio group element name is not unique in document):

function findSelection(field) {
    var formInputElements = document.getElementById("yourFormId").getElementsByTagName("input");
    alert(formInputElements);
        for (i=0; i < formInputElements.length; i++) {
        if ((formInputElements[i].type == "radio") && (formInputElements[i].name == field) && (formInputElements[i].checked)) {
            alert(formInputElements[i].value + ' you got a value');     
            return formInputElements[i].value;
        }
    }
}

HTML:

<form action="#n" name="theForm" id="yourFormId">
Answer
 <input type=radio name=rdbExampleInfo id=rdbExamples value="select 1">
 <input type=radio name=rdbExampleInfo id=rdbExamples value="select 2">
 <input type=radio name=rdbExampleInfo id=rdbExamples value="select 3">
 <input type=radio name=rdbExampleInfo id=rdbExamples value="select 4"> 

etc then use just

  $("#rdbExamples:checked").val()

Or

   $('input[name="rdbExampleInfo"]:checked').val();
Answer
    var value = $('input:radio[name="radiogroupname"]:checked').val();
Answer

Here's a nice way to get the checked radio button's value with plain JavaScript:

const form = document.forms.demo;
const checked = form.querySelector('input[name=characters]:checked');

// log out the value from the :checked radio
console.log(checked.value);

Source: https://ultimatecourses.com/blog/get-value-checked-radio-buttons

Using this HTML:

<form name="demo">
  <label>
    Mario
    <input type="radio" value="mario" name="characters" checked>
  </label>
  <label>
    Luigi
    <input type="radio" value="luigi" name="characters">
  </label>
  <label>
    Toad
    <input type="radio" value="toad" name="characters">
  </label>
</form>

You could also use Array Find the checked property to find the checked item:

Array.from(form.elements.characters).find(radio => radio.checked);

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